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  #1  
Old 01-12-2007, 06:03 PM
dagosto dagosto is offline
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Default Dynamic Convolution is real

http://www.acusticaudio.com/modules....le=nebula2free

There is a free version of this plug that can emulate eq, compressors, mic, phases, etc. The download process is incredibly wonky but this is surely worth a try for such a cutting edge product.

I've listened to it a bit. The compression seems very nice as does the eq. It is very heavy on the cpu though.
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Old 01-15-2007, 07:23 PM
Traveler Traveler is offline
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Ah, saw this plug at the KVR forums and gave it a shot, it wasn't too bad on CPU when compared to the current brew of low latency convolution processors (of course that can be pretty hefty already), did sound pretty good, but I am plenty satisfied with my Gigapulse / pristine space light combo for now, the technology is very cool anyhow though.
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Old 04-05-2007, 06:53 PM
alex_campos alex_campos is offline
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Hi Agosto
I don't if I am in the right thread, but anyways..
I watched the video where you recorded sine sweep to get the convolution. Does all the sine waves need to have the same amplitude or does they need to have the same power, like the pink noise?
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Old 04-05-2007, 07:33 PM
dagosto dagosto is offline
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I was talking about a different type of convolution but I'll try to answer your question alex_campos. And let me know if I missed the point of your question.

If you watched the second video you saw that the sine sweep was at -1dBfs across the entire spectrum. The way I think about it is that the sine sweep is at the same decibel level. I usually relate dB to power but it is related to both amplitude and power. So basically the digital sine sweep is an the same amplitude and the same power. Of course when we put it through the speakers it takes more power to output the lower frequencies. This means that acoustically there will be less power at the higher frequencies. That fit's with how sound moves through air though, high frequncies get eaten up and turned into heat much more easily.

Although this may not be the exact perfect method it works very well and is something anybody can do.
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Old 04-06-2007, 01:50 AM
alex_campos alex_campos is offline
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Sorry to post in the wrong thread.
Thank you.
You answered my question. Sometimes I get confused with the basics, I was thinking in a wrong way. It was good to remember that the dB is ratio of power, and doesn't represent the amplitude of the wave.
Congratulations for the site and forum.
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